0.09^2+2(0.09)b+b^2=1

Solution for 0.09^2+2(0.09)b+b^2=1 equation:

0.09^2+2(0.09)b+b^2=1

We move all terms to the left:

0.09^2+2(0.09)b+b^2-(1)=0

determiningTheFunctionDomain
b^2+2(0.09)b-1+0.09^2=0

We add all the numbers together, and all the variables

b^2+2(0.09)b-0.9919=0

We multiply parentheses

b^2+0.18b-0.9919=0

a = 1; b = 0.18; c = -0.9919;
Δ = b2-4ac
Δ = 0.182-4·1·(-0.9919)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.18)-2}{2*1}=\frac{-2.18}{2}
=-1+0.18/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.18)+2}{2*1}=\frac{1.82}{2}
=1/1.0989010989011
$